Diketahui fungsi m(x+1)=3x+5dan n(x)=1-2x2 maka(m0n)(3)

Langsung aja y

m(x+1) = 3x+5
misal :
x+1 = a
x = a-1

soal menjadi →
m(a) = 3(a-1) + 5
m(a) = 3a - 3 + 5
m(a) = 3a + 2

m(x) = 3x + 2

(mon)(x) = m{n(x)}

= 3n(x) + 2
= 3(1-2x²) + 2
= 3 - 6x² + 2
= 5 - 6x²

(mon)(3) = 5 - 6(3)²
(mon)(3) = 5 - 6(9)
(mon)(3) = 5 - 54
(mon)(3) = -49

Semoga berguna +_+