Kimia

Pertanyaan

Campuran 50 ml larutan CH3COOH 0,2M Dan 50ml KOH 0,2M memiliki pH...? (KaCH3COOH=10 pangkat -5

1 Jawaban

  • CH3COOH + KOH → CH3COOK + H2O

    → CH3COOH
    m = 50 x 0,2 = 10
    r = 10
    s = -

    → KOH
    m = 50 x 0,2 = 10
    r = 10
    s = -

    → CH3COOK
    m = -
    r = 10
    s = 10

    M = n / v
    M = 10 / 50 + 50
    M = 10 / 100
    M = 0,1 M

    → H2O
    m = -
    r = 10
    s = 10

    [OH-] = √Kw/Ka . [anion]garam
    [OH-] = √10^-14/10^-5 . 1 x 10^-1
    [OH-] = √10^-9 . 10^-1
    [OH-] = √10^-10
    [OH-] = 10^-5

    pOH = -log [OH-]
    pOH = -log 10^-5
    pOH = 5

    pH = 14 - 5
    pH = 9

Pertanyaan Lainnya