Campuran 50 ml larutan CH3COOH 0,2M Dan 50ml KOH 0,2M memiliki pH...? (KaCH3COOH=10 pangkat -5
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Campuran 50 ml larutan CH3COOH 0,2M Dan 50ml KOH 0,2M memiliki pH...? (KaCH3COOH=10 pangkat -5
1 Jawaban
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1. Jawaban Robinn
CH3COOH + KOH → CH3COOK + H2O
→ CH3COOH
m = 50 x 0,2 = 10
r = 10
s = -
→ KOH
m = 50 x 0,2 = 10
r = 10
s = -
→ CH3COOK
m = -
r = 10
s = 10
M = n / v
M = 10 / 50 + 50
M = 10 / 100
M = 0,1 M
→ H2O
m = -
r = 10
s = 10
[OH-] = √Kw/Ka . [anion]garam
[OH-] = √10^-14/10^-5 . 1 x 10^-1
[OH-] = √10^-9 . 10^-1
[OH-] = √10^-10
[OH-] = 10^-5
pOH = -log [OH-]
pOH = -log 10^-5
pOH = 5
pH = 14 - 5
pH = 9