diket ch3cooh ph 9+ log 2, ka 10*-5. tentukan konsentrasi
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diket ch3cooh ph 9+ log 2, ka 10*-5. tentukan konsentrasi
1 Jawaban
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1. Jawaban Robinn
→ CH3COOH → H+ + CH3COO-
→ pH = 9 + log2
pH = 9 + log2
pH = 9 + 0,3
pH = 9,3
pH = 10 - 0,7
pH = 10 - log5
pH = - log [H+]
10 - log5 = -log [H+]
[H+] = 5 x 10^-10