Diketahui fungsi f(x)=ax+b Jika f(-2)=9 dan f(3)=-1 Tentukan hasil dari f(2)

f(-2)= -2a+b = 9
f(3)= 3a+b= -1
(dikurangi)
-5a= 10
a= -2

f(-2)= -2a+b= 9
= -2(-2)+b= 9
=4+b= 9
b=9-4
b= 5

f(2)=2a+b=...
f(2)= 2(-2)+5= -4+5= 1

F(-2)= ax + b = 9
F(-2)= a(-2) + b = 9
= -2a + b = 9
F(3) = ax + b = -1
= a(3) + b = -1

F(-2) = -2a + b =9
F(3) = 3a + b = -1
________________-
= -5a = 10
a = 10/-5
a = -2

Cara mencari (b) =
3a+b = -1
3(-2) + b = -1
-6 + b = -1
b = -1 + 6
b = 5

Yang ditanya f(2) =
F(2) = ax + b
= -2(2) + 5
= -4 + 5
= 1