Tolong jawab Hitunglah massa garam (CH3COO)2Ca yang harus dilarutkan kedalam 10ml air agar diperoleh larutan garam dengan pH 9!(ka CH3COOH =1×10^-5 , Ar C =12

pH = 9
pOH = 5
OH- = 10^-5
OH- = akar Kw/Kb [Anion Garam]
10^-5= akar 10^-14/10^-5 [AG]
10^-10 = 10^-9 [AG]
[AG] = 10^-1 M
(CH3COO)2Ca ---> 2CH3COO- + Ca
[(CH3COO)2Ca] = 10^-1/2 = 0,05 M
[(CH3COO)2Ca] = m/Mr x 1000/v
0,05 = m/158 x 1000/10
m = 0,079 gram