Matematika

Pertanyaan

turunan parsial terhadap x dan y dari z = (x+y) len(xy)

1 Jawaban

  • z = uv
    z' = u'v + uv'

    z = (x + y) ㏑ (xy)
    ∂z / ∂x = (1 + 0) ㏑ (xy) + (x + y) [1 / (xy) y]
               = ㏑ (xy) + 1/x (x + y)
               = ㏑ (xy) + 1 + y/x

    z = (x + y) ㏑ (xy)
    ∂z / ∂y = (0 + 1) ㏑ (xy) + (x + y) [1 / (xy) x]
               = ㏑ (xy) + (1 / y) (x + y)
               = ㏑ (xy) + x/y + 1 

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