Matematika

Pertanyaan

diketahui f'(x) = 6x²-2x+4 dan f(-1)=-10, f(x)=

1 Jawaban

  • f(x) = int f'(x)
    f(x) = int (6x² - 2x + 4) dx
    = 2x³ - x² + 4x + c
    f(-1) = -10
    2(-1)³ - (-1)² + 4(-1) + c = -10
    -2 - 1 - 4 + c = -10
    c = -3
    f(x) = 2x³ - x² + 4x - 3

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