jika diketahui f(x)= x^2+2x-3. dengan daerah asal {-3,-2,-1,0,1,2,3}, maka berapa daerah hasilnya?? a.{-4,-3,-1,0,1,5,12} b.{-4,-3,0,5,12} c.{0,3,4,5,12} d.{-12

f(x) = x² + 2x - 3

f(-3) = (-3)² + 2(-3) - 3
f(-3) = 9 - 6 - 3
f(-3) = 0

f(-2) = (-2)² + 2(-2) - 3
f(-2) = 4 - 4 - 3
f(-2) = -3

f(-1) = (-1)² + 2(-1) - 3
f(-1) = 1 - 2 - 3
f(-1) = -4

f(0) = 0 + 0 - 3
f(0) = -3

f(1) = (1)² + 2(1) - 3
f(1) = 1 + 2 - 3
f(1) = 0

f(2) = (2)² + 2(2) - 3
f(2) = 4 + 4 - 3
f(2) = 5

f(3) = (3)² + 2(3) - 3
f(3) = 9 + 6 - 3
f(3) = 12

Sehingga daerah hasil = {-4,-3, 0, 5, 12}