minta tolongg jawab pertanyaan ini

1) sin tetha = depan/miring
= b/a

2) cos tetha = samping/miring
= 2(akar)2/3
#sin tetha = de/mi
1/3 = de/mi
#samping = (akar)mi^2-de^2
= (akar) 3^2 - 1^2
= (akar) 9-1
= (akar)8 = 2(akar)2

3) dan 4) e smua

5)cos^2 30 + sin^2 30 - 2cos 90
= 1 - 0 =1