tolong dibantu berserta pembahasannya soal sbm no 1 dan 2 ya makasih..

2) (2x)^(2 + 2log x) ≤ 16x^2
(2x)^2 . (2x)^(2log x) ≤ 16x^2
4x^2 . (2x)^(2log x) ≤ 16x^2
(2x)^(2log x) ≤ (16x^2)/(4x^2)
(2x)^(2log x) ≤ 4 ====> kedua ruas di 2log kan
2log (2x)^(2log x) ≤ 2log 4
(2log x) . 2log (2x) ≤ 2log 2^2
(2log x) . (2log 2 + 2log x) ≤ 2 . 2log 2
(2log x) (1 + 2log x) ≤ 2
Misal 2log x = a
a (1 + a) ≤ 2
a + a^2 ≤ 2
a^2 + a - 2 ≤ 0
(a + 2)(a - 1) ≤ 0
a = -2 atau a = 1
+++ [-2] --- [1] +++
-2 ≤ a ≤ 1
-2 ≤ 2log x ≤ 1
2log 2^-2 ≤ 2log x ≤ 2log 2
1/4 ≤ x ≤ 2