Matematika

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tolong di jawab dong. mau di kumpul besok 
Diketahui f(x) = (3p+2)x²-(2p+1)x+1. Jika F'(-1)=11, maka nilai f'(- ½p)-F(p)= ....

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    f(x) = (3p+2)x²-(2p+1)x+1
    maka
    f'(x) = 2(3p+2)x - (2p+1)
    f'(-1)=11
    11=-2(3p+2) - 2p - 1
    11= -6p-4-2p-1
    11=-8p-5
    -8p=-5-11
    -8p=-16
    p=-16/-8
    p=2

    maka
    jika p=2
    maka
    di dapat
    f'(x) = 2(3(2)+2)x - (2(2)+1)
    f'(x) = 16x - 5

    f'(-½p) = 16(-½(2)-5
    =-16-5
    =-21
    dan
    f(p) = 3(3(2)+2)(2²)-(2(2)+1))2+1
    = 12(8)-10+1
    =96-9
    =87

    maka
    f'(-½p) - f(p)
    =-21-87
    =-108

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