mohon bantuannya, soal sbmptn nih. trimakasih
SBMPTN
hanayni
Pertanyaan
mohon bantuannya, soal sbmptn nih. trimakasih
1 Jawaban
-
1. Jawaban arsetpopeye
34) Lim (√(3x + 3) - √(4x + 1)) / (2x - 4)(√(x + 2) + 2)
= Lim (√(3x + 3) - √(4x + 1)) / (2x - 4)(√(x + 2) + 2) . (√(3x + 3) + √(4x + 1)) / (√(3x + 3) + √(4x + 1))
= Lim ((3x + 3) - (4x + 1)) / (2x - 4)(√(x + 2) + 2)(√(3x + 3) + √(4x + 1))
= Lim (-x + 2) / (2x - 4)(√(x + 2) + 2)(√(3x + 3) + √(4x + 1))
= Lim -(x - 2) / 2(x - 2)(√(x + 2) + 2)(√(3x + 3) + √(4x + 1))
= Lim -1 / 2(√(x + 2) + 2)(√(3x + 3) + √(4x + 1))
= -1 / 2(√(2 + 2) + 2)(√(3.2 + 3) + √(4.3 + 1))
= -1 / 2(√4 + 2)(√9 + √9)
= -1 / 2(4)(6)
= -1/48
35) f(x) √{(x^2 + 4x + 4)/(25 - x^2)} terdefinisi jika
(x^2 + 4x + 4)/(25 - x^2) ≥ 0
(x + 2)(x + 2) / (5 - x)(5 + x) ≥ 0
x = -2 atau x = 5 atau x = -5
Garis bilangan
+++ (-5) --- [-2] --- (5) +++
x < -5 atau x > 5