Tentukan PH larutan yang terbentuk dari campuran 100 ml larutan CH3COOH 0,02 m dengan 59 ml larutan CH3COOH 0,1 M ka CH3COOH=1,5×10^5

[CH3COOH] = 0,02 x 100 = 2mmol
[CH3COO-] = 0,1 x 59 = 5,9 mmol

[H+] = Ka x [CH3COOH]/[CH3COO-]
[H+] = 1,5 x 10^-5 (2/5,9)
[H+] = 15 x 10^-6 (20 / 59)
[H+] = 15 x 10^-5 (2 / 59)
[H+] = 30/59 x 10^-5

pH = -log [H+]
pH = -log (30/59 x 10^-5)
pH = 5 - log30/59
pH = 5 - 0,3
pH = 4,7