Turunan pertama dari y = (1-x)² (2x+3). Mohon bantuannya

y' = u'v + uv'
u = (1-x)²
u'= 2.(1-x). -1
= -2(1-x) = -2+2x
v = 2x + 3
v'= 2
y' = (-2+2x)(2x+3) +(1-x)²(2)
= -4x-6+4x²+6x+(1+x²-2x)(2)
= 4x²+2x-6+2+2x²-4x
= 6x²-2x-4