diketahui luas selimut kerucut 550 cm².jika panjang garis pelukisnya 25cm tinggi kerucut adalah...

L = 550
phi×r×s = 550
22/7 × r × 25 = 550
r = 550 × 7/22 × 1/25
r = 3850/550
r = 7 cm

t = √s² - r²
  = √25² - 7²
  = √625 - 49
  = √576
  = √576
t = 24 cm

L = πrs
550 = 22/7 × r × 25
550 = 550/7 × r
r = 7/550 × 550
r = 7

t =√s² - r²
t =√ 25² - 7²
t = √625 - 49
t = √576
t = 24