jika 9log 2 = a dan 2log 3 = b, maka 6log 98

Dik:
⁷log2 = a ------->> ²log7 = 1/a
²log3 = b

Dit:
⁶log98 = ??

Jwb:
⁶log98
= ²log98 / ²log6
= (²log(7².2)) / (²log(3.2))
= (²log7² + ²log2) / (²log3 + ²log2)
= (2.²log7 + ²log2) / (²log3 + ²log2)
= (2.1/a + 1) / (b + 1)
= (2/a + 1) / (b + 1)
= (2 + a) / (a(b + 1))
= (a + 2) / (ab + a)