tentukan nilai p pada gambar berikut

9 : (9+3) = 12 : (12+p)
9 : 12. = 12 : (12+p)
12+p = 12 : (9 : 12)
= 12 × 12 : 9
= 16
p = 16 - 12
= 4

[tex] \frac{CD}{CA} = \frac{CE}{CB} = \frac{9}{(9+3)} = \frac{12}{CB} = \frac{9}{12} = \frac{12}{CB} [/tex]

CB =[tex] \frac{12 X 12}{9} = 16[/tex]

p = BE = CB - CE = 16 - 12 = 4.

jadi panjang p = 4cm