Diketahui f(x) = 6x/(xpangkat 2 -9) dan g(x) = √3x maka (f o g) (2)=

(fog)(x) = 6(√3x) / ((√3x)²-9)
= 6√3x / 3x - 9
= 6√3 / 3(x-3)
= 3√3x / (x-3)

(fog)(2) = 3(√3(2))/2-3
= 3√6 / -1
= -3√6