Jika titikbP(3,-2) dan titik A(2,3)maka tentukan bayangan titik P oleh dilatasi[A,-3]

Dilatasi (pusat (a,b), k)
x' = k(x-a)+a
y' = k(y-b)+b

P(x,y) = (3, -2) --> x = 3, y = 2
D{(a,b)=  (2,3),k =  -3) --> a= 2, b = 3 , k = -3

x' = k(x-a)+a --> x' = -3(3-2) + 2
x' = -3 + 2 = -1

y' = k(y-b) + b --> y' = -3(-2-3) + 3
y' = -3(-5) + 3
y'  = 18

P(3,-2) ----> P' (-1, 18)