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campuran yang terdiri dari 10 ml larutan asam asetat 0,1 M dan 5 ml larutan naoh 0,1M memiliki pH?

1 Jawaban

  • CH3COOH + NaOH → CH3COONa + H2O

    → CH3COOH
    m : 1mmol
    r : 0,5mmol
    s = 1 - 0,5 = 0,5mmol

    → NaOH
    m : 0,5mmol
    r : 0,5mmol
    s = 0,5 - 0,5 = 0

    → CH3COONa
    m : -
    r : 0,5mmol
    s = 0,5mmol

    → H2O
    m : -
    r : 0,5mmol
    s = 0,5mmol

    [H+] = Ka x (sisa garam / mmol garam)
    [H+] = 10^-5 (0,5mmol / 0,5mmol)
    [H+] = 10^-5

    pH = -log [H+]
    pH = -log10^-5
    pH = 5 - log1
    pH = 5 - 0
    pH = 5

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