Matematika

Pertanyaan

tolong bantu jawab no 22 dan 23 sama caranya ya
tolong bantu jawab no 22 dan 23 sama caranya ya

1 Jawaban

  • 22. f(x) = -3/x = -3x^(-1)

    f'(x) = -3×-1 x(-1-1) = 3x^(-2) = 3/x^2
    m = f'(-3) = 3/(-3)^2 = 3/9 = 1/3

    titik (-3, 1) ==> x1= -3 ; y1 = 1

    y= m(x-x1) + y1
    y= 1/3 ×(x+3)+ 1
    3y = x+3 + 3
    3y = x+6
    y = 1/3 x + 2


    23.
    y = 2x- x^2
    y' = 2 - 2x

    sejajar dgn garis x-y = 1 ==> m = -1/-1 = 1
    gradien(m) sama krn sejajar.
    y' = m
    2-2x = 1
    -2x = -1
    x = 1/2

    y = 2x- x^2
    y = 2×1/2 - (1/2)^2
    y = 1 - 1/4
    y = 3/4

    PGS

    y = 1×(x-1/2) + 3/4
    y = x - 1/2 + 3/4
    y = x + 1/4