tolong bantu jawab no 22 dan 23 sama caranya ya
Matematika
putrii85
Pertanyaan
tolong bantu jawab no 22 dan 23 sama caranya ya
1 Jawaban
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1. Jawaban keruasriki
22. f(x) = -3/x = -3x^(-1)
f'(x) = -3×-1 x(-1-1) = 3x^(-2) = 3/x^2
m = f'(-3) = 3/(-3)^2 = 3/9 = 1/3
titik (-3, 1) ==> x1= -3 ; y1 = 1
y= m(x-x1) + y1
y= 1/3 ×(x+3)+ 1
3y = x+3 + 3
3y = x+6
y = 1/3 x + 2
23.
y = 2x- x^2
y' = 2 - 2x
sejajar dgn garis x-y = 1 ==> m = -1/-1 = 1
gradien(m) sama krn sejajar.
y' = m
2-2x = 1
-2x = -1
x = 1/2
y = 2x- x^2
y = 2×1/2 - (1/2)^2
y = 1 - 1/4
y = 3/4
PGS
y = 1×(x-1/2) + 3/4
y = x - 1/2 + 3/4
y = x + 1/4