Diketahui A(3,1,0) , B(6,0,2) , C(x,y,6). Jika A,B,C kolinear (segaris), tentukan nilai x dan y

A, B , C Segaris

AB = kBC
B-A = k(C-B)
(6,0,2) - (3,1,0) = k((x,y,6) - (6,0,2))
(3,-1,2) = k((x-6), y , 4)

3 = k(x-6)...... (1)

-1 = ky ...... (2)

2 = k×4
k = 2/4
k = 1/2 .....(3)

(3) ke (1)
3 = 1/2 × (x-6)
6 = x - 6
x = 6+6
x = 12

(3) ke (2)
-1 = 1/2 × y
-2 = y
y = -2