tolong kak bantu jawab

Fungsi trigonometri

f(x)= (tan x + cos² x)/ (sin x)

tan 120 = tan (180-60) = - tan 60 = - √3
cos 120 = cos(180-60) = - cos 60 = - 1/2
sin 120 = sin (180-60) = sin 60 = 1/2 √3

f(120) =  ( tan 120 + (cos 120)³) / ( sin 120)
f(120) = (- √3 + (-1/2)³) / ( 1/2 √3)
f(120) = (-√3 - 1/8) /(1/2 √3)...kalikan (8√3)/(8√3)

f(120) = (8√3)(-√3 -1/8)  / (8√3)(1/2 √3)
f(120) = (-24 - √3) / (4(3))
f(120) = (-24 - √3) /(12)
f(120) =  - 1/12  (24 + √3)
..