tentukan turunan fungsi f(x)=(2x-3)/(4x+1)

u=(2x-3)
u'=2

v=(4x+1)
v'= 4

=u'v-uv'/v^2
=2(4x+3)-(2x-3)4/(4x+1)^2
=8x+6-8x+12/(4x+1)^2
=18/16x^2+8x+1
atau
=18/(4x+1)^2

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