diketahui f(x)=ax+b jika f(3)=-10dan f(-2)=5 berapa f(-6)?

f(3) = 3a + b = -10
f(-2) = -2a + b = 5
f(-6) = ???

jawab
3a + b = -10
-2a + b = 5
------------------ -
5a = -15
a = -15 : 5
a = -3

3a + b = -10
3(-3) + b = -10
-9 + b = -10
b = -10 + 9
b = -1

f(-6) = -6a + b
f(-6) = -6(-3) + (-1)
f(-6) = 18 - 1
f(-6) = 17

semoga membantu (^.^)(^.^)